- #1
Bob19
- 71
- 0
Hello
I'm suppose to show
Given z^4 + z^3 + z^2 + z + 1 = 0 where
[tex]z = cos(\frac{2 \pi}{5}) + i sin(\frac{2 \pi}{5})[/tex]
by using the binomial product formula.
r^n - s^n
Is that then
if r,s = z then z^4 - z^4 = 0 ?
Sincerely and Best Regards
Bob
I'm suppose to show
Given z^4 + z^3 + z^2 + z + 1 = 0 where
[tex]z = cos(\frac{2 \pi}{5}) + i sin(\frac{2 \pi}{5})[/tex]
by using the binomial product formula.
r^n - s^n
Is that then
if r,s = z then z^4 - z^4 = 0 ?
Sincerely and Best Regards
Bob