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clope023
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[SOLVED] Released Spring
A piece of cheese with a mass of 1.35kg is placed on a vertical spring of negligible mass and a force constant k = 1600N/m that is compressed by a distance of 12.3cm .
When the spring is released, how high does the cheese rise from this initial position? (The cheese and the spring are not attached.)
U1 = Ugrav1 + Uel1
U2 = Ugrav2
v1 = 0
v2 = 0
K1 = 0
K2 = 0
K1 + U1 = K2 + U2
--> Ugrav1 + Uel1 = Ugrav2
y1 = -.123m
(1.35kg)(9.81m/s^2)(-.123m) + 1/2k(-.123m)^2 = (1.35kg)(9.81m/s^2)h
h = ((1.35kg)(9.81m/s^2)(-.123m) + 1/2(1600N/m)(-.123m)^2))/((1.35kg)(9.81m/s^s))
h = .80m
it's incorrect and I'm not sure what I'm doing wrong, at the bottom position where the spring is compressed the initial position should be less than 0 correct?
there's no velocity at the inital position and at the highest point there is no velocity or potential energy, only gravity should be acting on it correct? any help is greatly appreciated.
Homework Statement
A piece of cheese with a mass of 1.35kg is placed on a vertical spring of negligible mass and a force constant k = 1600N/m that is compressed by a distance of 12.3cm .
When the spring is released, how high does the cheese rise from this initial position? (The cheese and the spring are not attached.)
Homework Equations
U1 = Ugrav1 + Uel1
U2 = Ugrav2
v1 = 0
v2 = 0
K1 = 0
K2 = 0
K1 + U1 = K2 + U2
--> Ugrav1 + Uel1 = Ugrav2
y1 = -.123m
The Attempt at a Solution
(1.35kg)(9.81m/s^2)(-.123m) + 1/2k(-.123m)^2 = (1.35kg)(9.81m/s^2)h
h = ((1.35kg)(9.81m/s^2)(-.123m) + 1/2(1600N/m)(-.123m)^2))/((1.35kg)(9.81m/s^s))
h = .80m
it's incorrect and I'm not sure what I'm doing wrong, at the bottom position where the spring is compressed the initial position should be less than 0 correct?
there's no velocity at the inital position and at the highest point there is no velocity or potential energy, only gravity should be acting on it correct? any help is greatly appreciated.