- #1
sambarbarian
- 68
- 0
Two cars leave one after the other and travel with acceleration 0.4 m/s^2 . Two minutes after the departure of the first vehicle , the distance between the cars becomes 1.9 km . The time interval between the departure of the cars is ?
i tried to do this by :- for First car (A)... 0.4 = Final V - 0 /120
therefore Final V is 48 m/s .
average V = 48 - 0 / 2 = 24
and 24 = d / 120 ... therefore distance = 24 * 120 .
now 24 * 120 - 1900 is the distance traveled by second car ( B ) ..
how should i proceed , if my logic is correct till now ?
i tried to do this by :- for First car (A)... 0.4 = Final V - 0 /120
therefore Final V is 48 m/s .
average V = 48 - 0 / 2 = 24
and 24 = d / 120 ... therefore distance = 24 * 120 .
now 24 * 120 - 1900 is the distance traveled by second car ( B ) ..
how should i proceed , if my logic is correct till now ?