- #1
tandoorichicken
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Heres an AP multiple choice problem that's giving me some trouble:
If [tex]\frac{\,dy}{\,dt} = ky [/tex] and k is a nonzero constant, then y could be
a) [itex] 2e^{kty}[/itex]
b) [itex] 2e^{kt}[/itex]
c) [itex] e^{kt} +3[/itex]
d) [itex] kty + 5 [/itex]
e) [itex] \frac{1}{2}ky^2 + \frac{1}{2}[/itex]
Dont quite know where to begin?
If [tex]\frac{\,dy}{\,dt} = ky [/tex] and k is a nonzero constant, then y could be
a) [itex] 2e^{kty}[/itex]
b) [itex] 2e^{kt}[/itex]
c) [itex] e^{kt} +3[/itex]
d) [itex] kty + 5 [/itex]
e) [itex] \frac{1}{2}ky^2 + \frac{1}{2}[/itex]
Dont quite know where to begin?