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- Thread starter rebo1984
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What do you get when you substitute each potential solution into the original equation?Hi,

If a = -1, what is the solution set of the equation sqrt (x+ a) = x −7

{5}

{10}

{5, 10}

No solution

(5,10) correct?

Thanks

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It works out.What do you get when you substitute each potential solution into the original equation?

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- #4

Let's try \(x=5\):It works out.

\(\displaystyle \sqrt{5-1}=5-7\)

\(\displaystyle 2=-2\)

Is this true?

- Jan 30, 2018

- 368

It works out.