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carpelumen
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1.
I figured out the first few, I just can't get the last one!
-The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.4° what is the index of refraction of the material?
1.54
-A light ray strikes this material (from air) at an angle of 37.9° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees).
37.9 deg
-Calculate the angle of the refracted ray (in degrees).
23.5 deg
Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.9° with respect to the normal. What is the angle of the refracted ray?
?
Refractive index x sin (theta)
[/B]
1.54 x sin (37.9) = .945999What am I doing wrong?
I figured out the first few, I just can't get the last one!
-The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.4° what is the index of refraction of the material?
1.54
-A light ray strikes this material (from air) at an angle of 37.9° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees).
37.9 deg
-Calculate the angle of the refracted ray (in degrees).
23.5 deg
Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.9° with respect to the normal. What is the angle of the refracted ray?
?
Homework Equations
Refractive index x sin (theta)
The Attempt at a Solution
[/B]
1.54 x sin (37.9) = .945999What am I doing wrong?