- #1
3.14159265358979
- 43
- 0
two charges of 1.5X10^-6 c and 3.0X10^-6 c are 0.2 m apart. Where is the electric field between them equal to zero?
heres what i got...
the electric field will be 0 when the field strength of the first charge minus the field strength of the second charge equals 0.
therefore,
q(1)-----x------P-------(0.2 - x)-------q(2)
where...
P is where the electric field equals 0
q(1) is the first charge
q(2) is the second charge
x is the distance (in metres) from the charge
[ kq(1) / (x)^2 ] - [ kq(2)/ ((0.2-x)^2) ] = 0
from here,
i cancel out the k's
find the common denominator and cancel it out once my numerator is expanded
try and use the quadratic equation to solve for x. however, when i try to solve for x i get a complex number...what am i doing wrong? the book says the answer is 0.08m (approx.) if you know a faster and much easier way, please do tell...thanks a bunch...
heres what i got...
the electric field will be 0 when the field strength of the first charge minus the field strength of the second charge equals 0.
therefore,
q(1)-----x------P-------(0.2 - x)-------q(2)
where...
P is where the electric field equals 0
q(1) is the first charge
q(2) is the second charge
x is the distance (in metres) from the charge
[ kq(1) / (x)^2 ] - [ kq(2)/ ((0.2-x)^2) ] = 0
from here,
i cancel out the k's
find the common denominator and cancel it out once my numerator is expanded
try and use the quadratic equation to solve for x. however, when i try to solve for x i get a complex number...what am i doing wrong? the book says the answer is 0.08m (approx.) if you know a faster and much easier way, please do tell...thanks a bunch...