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solve for f(x)=a^x

goosey00

Member
Sep 22, 2012
37
If you have f(x)=a^x and f(3)=64 what does f(2)=? Am I over thinking this one? Is it just f(2)=64 also?
 

SuperSonic4

Well-known member
MHB Math Helper
Mar 1, 2012
249
Re: solve for f(x)a^x

If you have f(x)=a^x and f(3)=64 what does f(2)=? Am I over thinking this one? Is it just f(2)=64 also?
f(b) means evaluate f(x) at the value b. In this case f(3) means find f(x) when x=3.

Since you have the constant $a$ you can find it's value from f(3) [64 is a cube number so $a$ is a whole number] as an intermediate step. You won't need a calculator for this one but as a hint $64 = 4^3$

  1. Solve $f(3)$ in terms of $a$ by substituting $x=3$ in $f(x)=a^x$
  2. Work out the value of $a$ from the above since you're told that f(3) = 64
  3. Use that value of $a$ to find $f(2) $ by substituting $x=2$
 

goosey00

Member
Sep 22, 2012
37
Re: solve for f(x)a^x

So it would be 4^2 so f(2)=16? right?
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Re: solve for f(x)a^x

Yes, since:

$\displaystyle a^3=4^3\,\therefore\,a=4\,\therefore\,f(x)=4^x\, \therefore\,f(2)=4^2=16$
 

HallsofIvy

Well-known member
MHB Math Helper
Jan 29, 2012
1,151
Re: solve for f(x)a^x

An equivalent way to do this would be to note that [tex]a^2= (a^3)^{2/3}= 64^{2/3}[/tex].
 
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