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Solve for F: C=9(F-32)/5

frctl

New member
Feb 28, 2020
6
How do I solve for F in

Screen Shot 2020-02-28 at 9.16.34 AM.png
 

topsquark

Well-known member
MHB Math Helper
Aug 30, 2012
1,120

frctl

New member
Feb 28, 2020
6
Is the following correct?

9/5C = 9/5F - 9/5(1/32)
C = F - 1/32
F = C + 1/32
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
644
Is the following correct?

9/5C = 9/5F - 9/5(1/32)
C = F - 1/32
F = C + 1/32
not quite ...

$C = \dfrac{9}{5}(F-32)$

as suggested by topsquark ...

${\color{red}\dfrac{5}{9}} \cdot C = {\color{red}\dfrac{5}{9}} \cdot \dfrac{9}{5}(F-32)$

$\dfrac{5}{9} \cdot C = \cancel{\dfrac{5}{9}} \cdot \cancel{\dfrac{9}{5}} ( F - 32)$ (note that any number times its reciprocal equals 1)

$\dfrac{5}{9} \cdot C = F - 32$

can you finish ?
 

frctl

New member
Feb 28, 2020
6
F = 9/5C + 32

Thank you!
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
644