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- #1

- Thread starter frctl
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- Thread starter
- #1

- Aug 30, 2012

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Hint: Multiply both sides of the equation by 5/9.How do I solve for F in

-Dan

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- #3

- Mar 1, 2012

- 980

not quite ...Is the following correct?

9/5C = 9/5F - 9/5(1/32)

C = F - 1/32

F = C + 1/32

$C = \dfrac{9}{5}(F-32)$

as suggested by topsquark ...

${\color{red}\dfrac{5}{9}} \cdot C = {\color{red}\dfrac{5}{9}} \cdot \dfrac{9}{5}(F-32)$

$\dfrac{5}{9} \cdot C = \cancel{\dfrac{5}{9}} \cdot \cancel{\dfrac{9}{5}} ( F - 32)$ (note that any number times its reciprocal equals 1)

$\dfrac{5}{9} \cdot C = F - 32$

can you finish ?

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- #5

- Mar 1, 2012

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