Welcome to our community

Be a part of something great, join today!

Solve exponential equation.

shorty888

New member
Apr 22, 2012
6
Solve 2^(4x-3)=1/8, find the exact answer
 

CaptainBlack

Well-known member
Jan 26, 2012
890
Re: Solve

Solve 2^(4x-3)=1/8, find the exact answer
Since \(1/8=2^{-3}\), you want to solve:

\(2^{4x-3}=2^{-3}\)

so, now can you do it?

CB
 

chisigma

Well-known member
Feb 13, 2012
1,704

shorty888

New member
Apr 22, 2012
6
Re: Solve

No, I don't understand.. I can't do it.. How??
 

chisigma

Well-known member
Feb 13, 2012
1,704
Re: Solve

No, I don't understand.. I can't do it.. How??
You have $\displaystyle a=b \implies \log_{2} a= \log_{2} b$, so that $\displaystyle a=2^{4x-3},\ b=\frac{1}{8} \rightarrow 4x-3=-3$ and we have a first order algebraic equation...

Kind regards

$\chi$ $\sigma$
 

CaptainBlack

Well-known member
Jan 26, 2012
890
Re: Solve

No, I don't understand.. I can't do it.. How??
In future please quote which post you are responding to (use the reply with quote option).

If you are refering to my post, the exponents on both sides are equal so: \(4x-3=-3\)

This is essentially the same as chisigma's method.

CB