# Solve equation with square roots

#### wishmaster

##### Active member
Can someone show me step by step guide,how to find all possible solutions for example?

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#### Opalg

##### MHB Oldtimer
Staff member
Can someone show me step by step guide,how to find all possible solutions for example?
Hi Andreas, and welcome to MHB. You do not say what you have tried in order to tackle this problem. I suggest that you start by looking at those square roots. Can you simplify them at all?

#### wishmaster

##### Active member
Thanks for welcome! I need to remove fractions,and get possible solutions for X. I dont know how to remove fractions,step by step would be very useful.

#### wishmaster

##### Active member
Is the solution x^3+3x^2=4?

#### Petrus

##### Well-known member
Hello,

Regards,
$$\displaystyle |\pi\rangle$$

#### wishmaster

##### Active member
Thanks Petrus, can you continue?

#### wishmaster

##### Active member
Or someone else? Its urgent. Thanks.

#### Petrus

##### Well-known member
Hello,
I Will post how to solve it after you post what you think you should do! Tips Dont do the homework in the last minutes

Regards,
$$\displaystyle |\pi\rangle$$

#### wishmaster

##### Active member
Expression skould be without fractions,and then i have to find possible solution(s) for X.

#### Petrus

##### Well-known member
Is the solution x^3+3x^2=4?
Hello,
My bad did not see this but that is correct! So what is x equal to?

Regards,
$$\displaystyle |\pi\rangle$$

#### wishmaster

##### Active member
I think it can be only one! True?

#### wishmaster

##### Active member
I want to know how do i get solution in math way. I can see that is 1,but how do i prove it? Can i "disassemble" my last expression? Or if you have time,show me please how would you do it! And many thanks,and sorry for my English!

#### Petrus

##### Well-known member
Hello,
$$\displaystyle x^2(x+3)=4$$ and you suspect that $$\displaystyle x=1,2,-2$$ BUT you always check if they are correct and Then you see that $$\displaystyle x=2,-2$$ is a fake root!

Regards,
$$\displaystyle |\pi\rangle$$

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