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Solve equation with square roots

wishmaster

Active member
Oct 11, 2013
211
Can someone show me step by step guide,how to find all possible solutions for example?
 

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Opalg

MHB Oldtimer
Staff member
Feb 7, 2012
2,702
Can someone show me step by step guide,how to find all possible solutions for example?
Hi Andreas, and welcome to MHB. You do not say what you have tried in order to tackle this problem. I suggest that you start by looking at those square roots. Can you simplify them at all?
 

wishmaster

Active member
Oct 11, 2013
211
Thanks for welcome! I need to remove fractions,and get possible solutions for X. I dont know how to remove fractions,step by step would be very useful.
 

wishmaster

Active member
Oct 11, 2013
211
Is the solution x^3+3x^2=4?
 

Petrus

Well-known member
Feb 21, 2013
739
Hello,


Regards,
\(\displaystyle |\pi\rangle\)
 

wishmaster

Active member
Oct 11, 2013
211
Thanks Petrus, can you continue?
 

wishmaster

Active member
Oct 11, 2013
211
Or someone else? Its urgent. Thanks.
 

Petrus

Well-known member
Feb 21, 2013
739
Hello,
I Will post how to solve it after you post what you think you should do! Tips Dont do the homework in the last minutes

Regards,
\(\displaystyle |\pi\rangle\)
 

wishmaster

Active member
Oct 11, 2013
211
Expression skould be without fractions,and then i have to find possible solution(s) for X.
 

Petrus

Well-known member
Feb 21, 2013
739
Is the solution x^3+3x^2=4?
Hello,
My bad did not see this but that is correct! So what is x equal to?

Regards,
\(\displaystyle |\pi\rangle\)
 

wishmaster

Active member
Oct 11, 2013
211
I think it can be only one! True?
 

wishmaster

Active member
Oct 11, 2013
211
I want to know how do i get solution in math way. I can see that is 1,but how do i prove it? Can i "disassemble" my last expression? Or if you have time,show me please how would you do it! And many thanks,and sorry for my English!
 

Petrus

Well-known member
Feb 21, 2013
739
Hello,
\(\displaystyle x^2(x+3)=4\) and you suspect that \(\displaystyle x=1,2,-2\) BUT you always check if they are correct and Then you see that \(\displaystyle x=2,-2\) is a fake root!

Regards,
\(\displaystyle |\pi\rangle\)
 
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