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- Thread starter 06Rousher
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- Nov 26, 2013

- 735

x = 2 + 1/x

To find x, I think it would be appropriate to multiply both sides with x, and solve the quadratic equation.

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So x^2-2x-1? Doesn't seem like that would be solvable.x = 2 + 1/x

To find x, I think it would be appropriate to multiply both sides with x, and solve the quadratic equation

I got 2.41 for x

- Nov 26, 2013

- 735

Why not? You did solve the equation:

x^2-2x-1 = 0 --> x = 1+/- sqrt(2)

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How did you get to x=1 +/- sqrt(2)?Why not? You did solve the equation:

x^2-2x-1 = 0 --> x = 1+/- sqrt(2)

- Nov 26, 2013

- 735

The quadratic equation: x

Discriminant: D = (-2)

The two solutions:

x1 = (2 + sqrt(8))/2 and x2 = (2 - sqrt(8))/2

or

x1 = 1 + sqrt(2) and x2 = 1 - sqrt(2)

In general for solving a quadratic equation:

\[ax^{2}+bx+c=0 \\\\D = b^{2}-4ac \\\\x = \frac{-b\pm \sqrt{D}}{2a}\]

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