- #1
NZS92
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Homework Statement
A potential difference of 24 kV maintains a downward-directed electric field between two horizontal parallel plates separated by 1.8 cm. Find the charge on an oil droplet of mass 2.2 x 10^-13 kg that remains stationary in the field between the plates.
Homework Equations
PE=KE
qV=(1/2)mv^2
V=Ed
E=k(q/r^2)
The Attempt at a Solution
PE=KE
qV=(1/2)mv^2
q=((1/2)mv^2)/V
If velocity is zero, then "q" is zero. Since its stationary. (I think the only way to find velocity is PE=KE)
I'm stucked at here, any solutions?