- #1
ScareCrow271828
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Homework Statement
The activation energy of vacany formation in Zinc is 72kj per mole. What is the vacancy concentration at 687k
Homework Equations
Nv=Nexp(-Q/kt)
N=p(Na/A)
The Attempt at a Solution
Seems very straight forward.
Although I keep getting zero for the exponent term.
Nv=(7,14g/cm^3)(6.02e23 atom/mole)/(65.382g/mol)xEXP((-72000J/mol/((1.3807E-23 J/k)(687k)=0
Something is definately fishy with the units. What am I missing? If I convert the Qv into eV/atom and use 8.61 eV/K I can get a number.
Thanks for your time.
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