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Homework Statement
http://www.strings.ph.qmul.ac.uk/~russo/QP/r06QPHYEX.pdf
Question 3.
The Attempt at a Solution
I can easily derive the equation I need, which is:
lamda = h/p
Which after some playing around with K.E =1/2mv^2 etc we obtain:
lambda (de brogile) = h/SQRT(2mKE)
Here is the data we are provided with in the exam (see sheet 1): http://www.strings.ph.qmul.ac.uk/~russo/QP/week6.pdf
Everythings in eV and MeV, I plug in the values constantly, tried converting h to joules, and the electron mass to kg etc, but no avail as I don't think I know what I am doing with it, and I can't seem to obtain the real answer which is: 1.2 x10^-9m
Anyone explain how to do this quickly? I understand the theory behind this top notch but missed on how to use eV etc.
THANKS.
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