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- Feb 14, 2012
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Solve the following system for real values of $a$ and $b$:
$2^{a^2+b}+2^{a+b^2}=8$
$\sqrt{a}+\sqrt{b}=2$
$2^{a^2+b}+2^{a+b^2}=8$
$\sqrt{a}+\sqrt{b}=2$
Hello.Solve the following system for real values of $a$ and $b$:
$2^{a^2+b}+2^{a+b^2}=8$
$\sqrt{a}+\sqrt{b}=2$
Hello.
I do not know. At a glance:
[tex]a=1 \ and \ b=1[/tex]
Regards.
Suggested solution by J. Chui:Solve the following system for real values of $a$ and $b$:
$2^{a^2+b}+2^{a+b^2}=8$
$\sqrt{a}+\sqrt{b}=2$