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The question goes as follows.

Solids of revolution. Find the volume of the solid of revolution. The region bounded by \(y= \frac{ln(x)}{\sqrt(x)}\), y=0 and x=2, revolved about the x-axis.

The problem I am having is trying to figure out how to separate the top and bottom of this fraction. These are some of the things I've looked at, but I don't think I can integrate any of them.

\([x^{\frac{1}{2}} * ln(x)]^2\)

\(\frac{[ln(x)]}{x}\)

And a few others.

I know that I have to integrate with \(\int \pi[\frac{[ln(x)]}{x}]dx\) from 1 to 2 ( I don't know how to get the limits on the integral)

Any help would be very much appreciated. This doesn't seem to be too hard of a problem, but I can't figure out how to get these separated so I can integrate.

Thanks,

Mac