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- Thread starter Katsa333
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- Mar 5, 2012

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Hi Katsa333 ! Welcome to MHB!I don't really know how to start with this question. Please help?

For the function g: [0,5] \implies R, g(x)=(x+3)/(2)(R=Real Numbers)

sketch the graph of y=g(x)

I don't know how the [0,5] \implies R changes the graph.

Properly we have the function $g: [0,5] \to \mathbb R$ given by $g(x)=\frac{x+3}{2}=\frac 12 x + \frac 32$.

The first part does not change the graph, other than defining its domain [0,5], meaning it begins at x=0 and ends at x=5.

The second part is the equation of a line that slopes up by $\frac 12$ when we move $1$ to the right.

And it intercepts the y-axis at $y=\frac 32$.

Now what will the graph look like?

- Jan 30, 2018

- 376

Katsa333, "→" here is NOT "implies", it is simply "to" or "goes to". As I like Serena said, the graph of the equation y= (x+ 3)/2 is a straight line, with slope 1/3 and y-intercept 3/2. Restricting x to [0, 1] means that the graph is only the part of that line that lies above [0, 1] on the x-axis. It is the line