So try numbers between 0 and 180!ibysaiyan said:Homework Statement
The function f with domain 0[tex]\leq[/tex]x[tex]\leq180[/tex]
is defined by f(x)=2sinx/Sketch and find the range of f.
Homework Equations
The Attempt at a Solution
well..i haven't got a clue, if i try to get value for 2sin(0) gives me zero and for 2sin(180) gives me the same answer =/.Thanks in advance.
The range of a function is the set of all possible output values. In this case, the range of f(x) = 2sin(x) is [-2, 2], meaning that the output values can range from -2 to 2.
To sketch the graph of f(x) = 2sin(x), you can use the unit circle and plot points for different values of x. The graph will have a sinusoidal shape, with a maximum value of 2 and a minimum value of -2.
The period of a function is the distance between two consecutive points on the graph that have the same value. For f(x) = 2sin(x), the period is 2π, meaning that the graph repeats itself every 2π units along the x-axis.
The coefficient 2 affects the amplitude of the function, which is the distance between the maximum and minimum values on the graph. In this case, the amplitude is 2, meaning that the graph will oscillate between 2 and -2 along the y-axis.
No, the coefficient 2 only affects the amplitude of the function, not the range. The range will always be [-2, 2] for f(x) = 2sin(x).