- #1
saganforever
- 12
- 0
This is not a homework question, my friend just wanted me to consult math experts to make him feel safer.
My friend is building a ramp for us to make the jump over 2 cars. I weigh 120 pounds, and my friend weighs 135 pounds. I figured the ramp needs to be anywhere from 6 - 8 ft. high. We are jumping over a Ford Escape (~5.8ft. tall, ~5.8ft wide) and a Chevy Cobalt (~4.76ft. tall, ~5.8in. wide). We will be holding onto the back of another car in order to get speed, and we need to know how fast we need to go depending on how high the ramp is and how much of a curve it has on it. I figure the ideal distance to land away from the edge of ramp is about 12.5 ft ([5.8 x 2]+ extra room between cars and ramp).
not sure but
s = ut + 0.5at^2
u is initial velocity of the object
t is time taken to reach max height
a is deceleration due to gravity (-9.81 m/s^2)
Do not worry about our safety, we are very experienced and not holding anyone responsible in case we get hurt.
Homework Statement
My friend is building a ramp for us to make the jump over 2 cars. I weigh 120 pounds, and my friend weighs 135 pounds. I figured the ramp needs to be anywhere from 6 - 8 ft. high. We are jumping over a Ford Escape (~5.8ft. tall, ~5.8ft wide) and a Chevy Cobalt (~4.76ft. tall, ~5.8in. wide). We will be holding onto the back of another car in order to get speed, and we need to know how fast we need to go depending on how high the ramp is and how much of a curve it has on it. I figure the ideal distance to land away from the edge of ramp is about 12.5 ft ([5.8 x 2]+ extra room between cars and ramp).
Homework Equations
not sure but
s = ut + 0.5at^2
u is initial velocity of the object
t is time taken to reach max height
a is deceleration due to gravity (-9.81 m/s^2)
Do not worry about our safety, we are very experienced and not holding anyone responsible in case we get hurt.