- #1
kostantina
- 10
- 0
Find the phase angle between i_1= - 4 sin(377t+55) and i_2= 5 cos(377t-65)
Ok, so I converted i_1= 4 cos(377t+145) and i_2=5cos(377t-65)
According to lectures in class the 'most' negative leads. So in this case i_2 leads by -65-145=210. However, if you look at the publishers solution it says that i_1 leads by 210. Why? Any feedback would be greatly appreciated. Thank you.
Here is a link to the publishers solution posted online on his student edition help/tools website:
Its problem 9.2
http://highered.mcgraw-hill.com/sites/dl/free/0073380571/938372/Chapt09PP_120121.pdf
The Attempt at a Solution
Ok, so I converted i_1= 4 cos(377t+145) and i_2=5cos(377t-65)
According to lectures in class the 'most' negative leads. So in this case i_2 leads by -65-145=210. However, if you look at the publishers solution it says that i_1 leads by 210. Why? Any feedback would be greatly appreciated. Thank you.
Here is a link to the publishers solution posted online on his student edition help/tools website:
Its problem 9.2
http://highered.mcgraw-hill.com/sites/dl/free/0073380571/938372/Chapt09PP_120121.pdf
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