Quantum Fizzics said:Homework Statement
At what angle will 750nm light produce a second minimum if the single-slit width is 2.0um
Homework Equations
Sin(theta)=n(lambda)/w
The Attempt at a Solution
This is what I got so far
(theta)=sin-1(3x10^-6/2x10^-6)
the answer btw is 49degrees
It's because you are asking for an angle with sin > 1.Quantum Fizzics said:I don't understand why I keep getting error on my calculator
A single slit problem is a phenomenon in which light is diffracted or bent as it passes through a narrow opening or slit. This can result in a pattern of light and dark bands, known as interference fringes, being observed on a screen behind the slit.
The wavelength of light has a direct impact on the diffraction pattern observed in a single slit problem. 750nm light falls in the visible spectrum and is commonly used in experiments to demonstrate diffraction patterns.
The width of the slit is directly proportional to the spacing of the interference fringes in the diffraction pattern. A wider slit will result in a wider spacing between fringes, while a narrower slit will result in a smaller spacing between fringes.
2.0um (micrometers) is considered a narrow slit because it is significantly smaller than the wavelength of light being used (750nm). When the width of the slit is comparable to the wavelength of light, the diffraction pattern becomes more complex and difficult to analyze.
Yes, the principles of diffraction and interference observed in single slit problems can be applied to other types of waves, such as sound waves and water waves. However, the specific equations and calculations may differ depending on the properties of the wave being studied.