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- #1
- Feb 14, 2012
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Solve the following system in real numbers:
\(\displaystyle a^2+b^2=2c\)
\(\displaystyle 1+a^2=2ac\)
\(\displaystyle c^2=ab\)
\(\displaystyle a^2+b^2=2c\)
\(\displaystyle 1+a^2=2ac\)
\(\displaystyle c^2=ab\)