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- Thread starter dmarley
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z^(4*(-5)) = z^(-20)(x^{-2}y^{10})^{3}/ (x^{-4}yz^{4})^{-5}

This one throws me off because I don't know how to deal with the z, as only on the right side of the divide

Now move to numerator:

z^(-20) = z^20

So you'll end up with: y^35 * z^20 / x^26

- Aug 30, 2012

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The basic rule is \(\displaystyle a^{-1} = \dfrac{1}{a}\) and \(\displaystyle \left ( a^{-1} \right ) ^{-1} = a\).Helping my daughter with her math and hit this one and not sure how to advise. All help welcome

(x^{-2}y^{10})^{3}/ (x^{-4}yz^{4})^{-5}

This one throws me off because I don't know how to deal with the z, as only on the right side of the divide

Strategy: Get rid of those pesky negative powers.

\(\displaystyle \dfrac{ \left ( x^{-2}y^{10} \right ) ^3 }{ \left ( x^{-4} y z^4 \right ) ^{-5} }\)

\(\displaystyle = \left ( x^{-2}y^{10} \right ) ^3 \left ( x^{-4} y z^4 \right ) ^5\)

\(\displaystyle = \left ( \dfrac{y^{10}}{x^2} \right ) ^3 \left ( \dfrac{yz^4}{x^4} \right ) ^5\)

Can you finish?

-Dan

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