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- Thread starter dlecl
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The answer to your question is not really because there is not a common factor in the polynomial.four variables a,b,c,d

here is the equation: a+b+c+d+2(ab+ac+ad+bc+bd+cd)+4(abc+abd+acd+bcd)+8(abcd)

wondering if this can be simplified to something much smaller

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- Feb 7, 2012

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You could write it as $\frac12(2a+1)(2b+1)(2c+1)(2d+1) - \frac12$, if that helps.four variables a,b,c,d

here is the equation: a+b+c+d+2(ab+ac+ad+bc+bd+cd)+4(abc+abd+acd+bcd)+8(abcd)

wondering if this can be simplified to something much smaller