- #1
GarrettB
- 12
- 0
Homework Statement
The velocity of an object in simple harmonic motion is given by v(t)= -(4.04m/s)sin(21.0t + 1.00π), where t is in seconds. What is the first time after t=0.00 s at which the velocity is -0.149m/s?
Homework Equations
N/A
The Attempt at a Solution
I thought this was an easy question but there must be a flaw somewhere in my logic. I've tried -0.149=-4.04*sin(21t+pi). However, solving for t gives me a negative number. I've also tried doing using cos instead of sin to get rid of the phase constant, but still the wrong answer. It's given me aprrox. 0.07s. Any help would be appreciated