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Homework Statement
An object undergoing SHM with a period 0.9s and amplitude of 0.32 m at t=0 the object is at 0.32 m and is instantaneously at rest. Calculate the time it takes the object to go a) from 0.32 to 0.16 m
b) from 0.16 m to 0
i can do a but don't understand why when i do the calculation x is not -1/2 and is 1/2
Homework Equations
x=Asin(wt)
The Attempt at a Solution
so for first part 1/2 = 0.32 cos (2+2/9)*pi * t
i get 0.15 correct answer and for part b i do the same thing because it is the same distance excpt i shift the graph so t1 is at 0.16 like this 0.16 = a cos ((wt) - pi/4)