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Ithryndil
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[SOLVED] Simple Harmonic Motion, Finding Time
A 0.400 kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm.
Calculate the time interval required for the object to move from x = 0 to x = 4.00 cm.
The relevant equations for this should be:
x = Acos(ωt)
w = [tex]\sqrt{k/m}[/tex]
You should be able to solve the above equation for t...
cos(ωt) = x/A
ωt = arccos(x/A)
[tex]t = arccos(x/A)/\sqrt{k/m}[/tex]
Plugging in the following values:
x = 4 cm
A = 10 cm
k = 8 N/m
m = 0.400 kg
I get that t = .259s which is not right. Where am I going wrong?
Homework Statement
A 0.400 kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm.
Calculate the time interval required for the object to move from x = 0 to x = 4.00 cm.
Homework Equations
The relevant equations for this should be:
x = Acos(ωt)
w = [tex]\sqrt{k/m}[/tex]
The Attempt at a Solution
You should be able to solve the above equation for t...
cos(ωt) = x/A
ωt = arccos(x/A)
[tex]t = arccos(x/A)/\sqrt{k/m}[/tex]
Plugging in the following values:
x = 4 cm
A = 10 cm
k = 8 N/m
m = 0.400 kg
I get that t = .259s which is not right. Where am I going wrong?