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pat666
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A hanging wire is 1.80 m long. When a 60.0 kg ball is suspended from the wire, the wire stretches 2.00 mm. If the ball is pulled down a small additional distance and released, at what frequency will it vibrate? Assume that the stress on the wire is less than the proportional limit.
I have found an answer but it seems too simple and does not take into account the length of the wire but I am pretty sure that it should. any help is appreciated. thanks
F=kx
T=2pi*sqrt(m/k)
f=1/T
Found the spring constant to be 294300n/m
then found the period of oscillation to be 0.0897s
then inverted it to find the frequency to be 11.15hz
I have found an answer but it seems too simple and does not take into account the length of the wire but I am pretty sure that it should. any help is appreciated. thanks
Homework Equations
F=kx
T=2pi*sqrt(m/k)
f=1/T
The Attempt at a Solution
Found the spring constant to be 294300n/m
then found the period of oscillation to be 0.0897s
then inverted it to find the frequency to be 11.15hz