- #1
pezzang
- 29
- 0
Hi, I had problem solving one question.
Please help me. I included my answers. Please check to make sure that my way is right.
1. IF f(x,y) = x^2 +4y^2, find the gradient vector f(2,1) and use it to find the tanenet line to the level curve f(x,y) = 8 in the xy-plane at the point (2,1).
I solved this way:
f(x,y) = x^2 + 4y^2
gradient f(x,y) = <fsubx, fsuby>
fsubx = 2x
fsuby = 8y
therefore, gradient f(x,y) = <2x,8y>
gradient f(2,1) = <4,8>
f(x,y) = 8
HOW DO I FIND THE EQUATION OF TANGENT LINE?
- I know how to find the equation of tangent plane, but i don't know how to find line. If you can tell me how to find it, i would greatly appreciate your help and intellect.
AND, please make sure that What i did until now is right.
Thank you so much.
Please help me. I included my answers. Please check to make sure that my way is right.
1. IF f(x,y) = x^2 +4y^2, find the gradient vector f(2,1) and use it to find the tanenet line to the level curve f(x,y) = 8 in the xy-plane at the point (2,1).
I solved this way:
f(x,y) = x^2 + 4y^2
gradient f(x,y) = <fsubx, fsuby>
fsubx = 2x
fsuby = 8y
therefore, gradient f(x,y) = <2x,8y>
gradient f(2,1) = <4,8>
f(x,y) = 8
HOW DO I FIND THE EQUATION OF TANGENT LINE?
- I know how to find the equation of tangent plane, but i don't know how to find line. If you can tell me how to find it, i would greatly appreciate your help and intellect.
AND, please make sure that What i did until now is right.
Thank you so much.