- Thread starter
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Petrus
Well-known member
- Feb 21, 2013
- 739
Hello MHB,
I am working with a exemple that I think they got some incorrect.
Exemple 10.Show that diagonals in a diamond(romb) is orthogonal.
I understand that \(\displaystyle AC•BD=0\) cause of dot product and if it's orthogonal the angle is \(\displaystyle \frac{\pi}{2}\)
I understand all the part until the step before the last one
Edit: last part got cut in picture, it should be: \(\displaystyle |BC|^2-|AB|^2=0\)
Regards,
\(\displaystyle |\pi\rangle\)
I am working with a exemple that I think they got some incorrect.
Exemple 10.Show that diagonals in a diamond(romb) is orthogonal.
I understand that \(\displaystyle AC•BD=0\) cause of dot product and if it's orthogonal the angle is \(\displaystyle \frac{\pi}{2}\)
I understand all the part until the step before the last one

Edit: last part got cut in picture, it should be: \(\displaystyle |BC|^2-|AB|^2=0\)
Regards,
\(\displaystyle |\pi\rangle\)
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