- Thread starter
- Admin
- #1

- Feb 14, 2012

- 3,906

This question seems easy but I have tried many different ways to find the proof, still I couldn't get through. Could someone please walk me through this problem?

Thanks in advance.

Question:

If \(\displaystyle \alpha\) is a real root of \(\displaystyle x^5-x^3+x-2=0\), show that \(\displaystyle \alpha^6=3\)