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Amr719
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Amr719 said:I can't understand the solution and what is the variable "X" !
One of the loads on the beam is the distributed load of 3 kips/ft, applied between points A and C.Amr719 said:Yes , but it is considered part of the force in the " ∑Fy " . That's what I cannot understand
What don't you understand about distributed loads? You know, loads spread out over a certain distance along a beam, say.Amr719 said:No
Shear in a beam is a type of force that causes one part of the beam to move in a direction parallel to its cross-section. It is a result of external loads acting on the beam, causing it to deform and experience internal forces.
Bending in a beam is a type of deformation that occurs when a beam is subjected to external loads. It causes the beam to curve or bend along its length, resulting in internal stresses and strains.
Stress in a beam is the internal force per unit area that is caused by external loads. It is a measure of how much force is acting on a specific area of the beam and is typically expressed in units of force per unit area, such as pounds per square inch (psi) or newtons per square meter (N/m²).
Shear and bending both cause internal forces and stresses in a beam, which can lead to structural failure if they exceed the beam's strength. Shear can cause the beam to deform and twist, while bending can cause it to bend or break.
There are various equations and formulas that can be used to calculate shear, bending, and stress in a beam, depending on the specific loading conditions and beam properties. These calculations can be done using advanced mathematical methods or with the help of computer software programs, such as finite element analysis. It is important to consider all of the external forces and loads acting on the beam to accurately determine the internal forces and stresses.