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#### TracyThomas

##### New member

- Oct 4, 2012

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__I have this problem in my book:__

Ann had 20 less than Betty. Ann spent 3/4 of her money, while Betty spent 4/5 of hers. Then Ann's remainder was 5/6 of Betty's remainder. If Ann had x originally, form an equation in x and solve it.

__And this solution in the answer key:__

x=Ann's x+20=Betty's

Remainder of Ann's money = 1/4x

Remainder of Betty's money = 1/5(x+20)

1/4x = 5/6 (1/5(x + 20))

x/4 = x/6 + 50/3

12(x/4) = 12(x/6) + 12(50/3)

3x = 2x + 40

Survey says:

x = 40

__The question is: How did the 50 in 50/3 get there?__

Can someone please explain that step so both me and my homeschool teacher can understand it?