# [SOLVED]set equality

#### Fermat

##### Active member
Am I right in thinking that if we have 3 sets A,B,C, then with A intersect B represented as AB, we have:

A(B\C)=(AB)\C=B(A\C)?

#### mathbalarka

##### Well-known member
MHB Math Helper
Yes. This follows from the definition of set minus.

#### Evgeny.Makarov

##### Well-known member
MHB Math Scholar
All three sets equal $A\cap B\cap\bar{C}$ where $\bar{C}$ is the complement of $C$.