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#### veronica1999

##### Member

- Jun 4, 2012

- 63

Could I get some help please?

Let T1 be a triangle with sides 2011, 2012, and 2013. For n > = 1, if Tn = triangle ABC

and D, E, and F are the points of tangency of the incircle of triangle ABC to the

sides AB, BC, and AC, respectively, then Tn+1 is a triangle with side lengths

AD, BE, and CF, if it exists. What is the perimeter of the last triangle in the

sequence (Tn) ?

The answer is 1509/28.

Please do not laugh at my solution.

6036/2 , 6036/4 ,6036/8 ......... 6036/4096.

I put 4096 as the last term because the next one is 8192

My answer 6036/4098 = 1509/1024

Let T1 be a triangle with sides 2011, 2012, and 2013. For n > = 1, if Tn = triangle ABC

and D, E, and F are the points of tangency of the incircle of triangle ABC to the

sides AB, BC, and AC, respectively, then Tn+1 is a triangle with side lengths

AD, BE, and CF, if it exists. What is the perimeter of the last triangle in the

sequence (Tn) ?

The answer is 1509/28.

Please do not laugh at my solution.

6036/2 , 6036/4 ,6036/8 ......... 6036/4096.

I put 4096 as the last term because the next one is 8192

My answer 6036/4098 = 1509/1024

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