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cheatmenot
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\(\displaystyle (2xy-3y)dx-({x}^{2}-x)dy=0\)
ans. \(\displaystyle xy(x-3)=C\)
ty
ans. \(\displaystyle xy(x-3)=C\)
ty
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cheatmenot said:\(\displaystyle (2xy-3y)dx-({x}^{2}-x)dy=0\)
ans. \(\displaystyle xy(x-3)=C\)
ty
cheatmenot said:i need the solution in the given problem . .i found out in my book the answer . .i need the solution on how to solve the problem using the separation of variables
cheatmenot said:\(\displaystyle (2xy-3y)dx-({x}^{2}-x)dy=0\)
ans. \(\displaystyle xy(x-3)=C\)
ty
laura123 said:$\displaystyle\dfrac{2x-3}{x^2-x}dx=\dfrac{dy}{y}\Rightarrow\ \int\dfrac{2x-3}{x^2-x}dx=\int\dfrac{dy}{y}$
$y=\dfrac{kx^3}{x-1}$
The separation of variables problem is a mathematical technique used to solve differential equations. It involves breaking down a complex equation into simpler equations that can be solved separately, and then combining those solutions to find the overall solution.
Separation of variables is important in science because it allows us to find solutions to complex problems that would otherwise be difficult or impossible to solve. It is particularly useful in fields such as physics and engineering where differential equations are commonly used to model real-world systems.
Some common applications of separation of variables include solving heat conduction equations, wave equations, and Schrödinger's equation in quantum mechanics. It is also used in fields such as fluid dynamics, electromagnetism, and astrophysics.
The first step is to identify the differential equation and determine if it can be solved using separation of variables. Then, the equation is separated into simpler equations by isolating the variables on opposite sides of the equation. Next, each equation is solved separately using integration or other mathematical techniques. Finally, the solutions are combined to find the overall solution to the original equation.
While separation of variables is a powerful technique, it is not always applicable to all types of differential equations. It can only be used for linear, homogeneous equations, and the variables must be separable. Additionally, the technique may not always yield a complete solution and may require additional conditions or assumptions to be made.