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#### find_the_fun

##### Active member

- Feb 1, 2012

- 166

\(\displaystyle \frac{dy}{dx} = e^{3x+2y}\)

Break up \(\displaystyle e^{3x+2y} = e^{3x}e^{2y}\) Move x's and y's to their own side of the equation.

\(\displaystyle \frac{1}{e^{2y}} dy = e^{3x} dx\)

Integrate both sides of the equation to get \(\displaystyle \frac{-e^{2y}}{2x}=\frac{e^{3x}}{3}+C\)

I don't know how to isolate the y; I don't know how to get it down from the exponent.