Semiconductor Diodes: Calculating Rf and Why VD=0

In summary, when proving the ideal diode's short circuit in forward biasing, we calculate the diode's resistance (Rf) by dividing the forward voltage by the forward current. However, we put VD=0 in the calculation because it is assumed that the ideal diode has no voltage drop. This assumption makes other calculations easier. If we want to consider a non-ideal diode, we can measure the forward voltage in the way described.
  • #1
Ghassan99
17
0
Semiconductor dioedes !

when proving that the ideal diode is short circuit in forward biasing we calculate the diode Resistance Rf which is equal to the diode forward voltage upon it's forward current ...but why we put VD=0 why?
 
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  • #2


These are two different things.

An ideal diode is one that nobody has invented yet, but we assume we have one just to make the other calculations easier. If you are using a diode to rectify 30 volts AC then a voltage drop of 0.6 volts may be a trivial error which can be ignored.

If we don't want to regard the diode as ideal, then we can measure the forward voltages in the way you described.
 
  • #3


Thank you :)
 

Related to Semiconductor Diodes: Calculating Rf and Why VD=0

1. How do you calculate the forward resistance (Rf) of a semiconductor diode?

To calculate Rf, you can use the equation Rf = Vf/If, where Vf is the forward voltage drop across the diode and If is the forward current through the diode. This equation assumes that the diode is operating in its forward-biased region.

2. Why is VD always equal to 0 in a semiconductor diode?

In a semiconductor diode, VD refers to the voltage drop across the diode. In an ideal diode, VD is always equal to 0 because any voltage applied in the reverse direction will not result in any current flow. However, in practical diodes, there may be a small reverse current, leading to a small voltage drop, but it is typically negligible.

3. What is the significance of calculating Rf in a semiconductor diode?

Calculating Rf in a semiconductor diode is important because it helps us understand the efficiency and performance of the diode. A lower Rf value indicates that the diode is more efficient in allowing current to flow in the forward direction, while a higher Rf value may indicate potential issues or limitations with the diode.

4. Can you explain the concept of forward-bias in a semiconductor diode?

Forward-bias refers to the condition in which the anode of the diode is connected to the positive side of a voltage source, and the cathode is connected to the negative side. This allows current to flow easily through the diode, as the positive voltage attracts the majority charge carriers (holes) towards the junction, while the negative voltage repels the minority charge carriers (electrons) away from the junction.

5. How does the voltage drop (Vf) across a semiconductor diode change with increasing forward current (If)?

The voltage drop across a semiconductor diode (Vf) increases slightly with increasing forward current (If). This is because as the current increases, more charge carriers are being pushed through the diode, leading to a slight increase in the voltage drop. However, this increase is typically minimal and can be considered negligible in most practical applications.

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