- #1
Cod
- 325
- 4
Problem is:
2 cos 3x - 1 = 0
Here's how I've done it so far:
2 cos 3x = 1
cos 3x = 1/2
Now I'm stuck. Where do I go from here? Do I divide the 3 out making it cos x = 1/6? I know how to find all the real solutions once I find what cos x is. I'm just having trouble figure out exactly how to get cos x in that type of problem.
Any help is grealy appreciated.
2 cos 3x - 1 = 0
Here's how I've done it so far:
2 cos 3x = 1
cos 3x = 1/2
Now I'm stuck. Where do I go from here? Do I divide the 3 out making it cos x = 1/6? I know how to find all the real solutions once I find what cos x is. I'm just having trouble figure out exactly how to get cos x in that type of problem.
Any help is grealy appreciated.
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