Hi markosheehan ,can someone help me with the 1989 question.
i think part i is k2(c03)
for ii the gas given of is co2. 1 one the precipitates given off was caco3. i am not sure what the other was. is it supposed to be a reaction between mgso4 +k2co3?
Potassium is in group 1, meaning it has a single electron in its outer shell that it is eager to release, becoming an ion that is dissolved in water.thanks for your help
how did you know "Since K is very soluble, the precipitate must be from Mg."
is it just a general rule you just learn off that potassium is more soluble than mg. just because k is more soluble than mg how did you know mg would join with the (co3)^2-