- Thread starter
- #1

#### karush

##### Well-known member

- Jan 31, 2012

- 2,678

3.7.4. The sum of two positive numbers is 16.

What is the smallest possible value of the sum of their squares?

$x+y=16\implies y=16-x$

Then

$x^2+(16-x)^2=2 x^2 - 32x + 256$

So far

... Hopefully

What is the smallest possible value of the sum of their squares?

$x+y=16\implies y=16-x$

Then

$x^2+(16-x)^2=2 x^2 - 32x + 256$

So far

... Hopefully

Last edited: