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I have posted a link there to this thread so the OP can view my work.Need help with derivatives please!?

All answers involve a unit of dollars, so you must enter your answers accurate to two decimal places!

A factory owner who employes m workers finds that they produce

q= 1.8m(1.8m+18)^3/2 units of product per day.

The total revenue R in dollars is

R=1312q / (24660+5q)^1/2

(a) From the fact that

revenue =(price per unit)*(number of units)

it follows that

R=(price per unit)*q

So when there are 10 workers, the price per unit is ? dollars.

(b) When there are 10 workers, the marginal revenue is ? dollars/(one unit of product).

(c) The marginal-revenue product is defined as the rate of change of revenue with respect to the number of employees. Therefore,

marginal-revenue product=dR/dm

If q and R are given as above then, when m= 10, the marginal-revenue product is ? dollars/(one worker). This means that if employee number 11 is hired, revenue will increase by approximately ? dollars per day.

I tried substituting 10 for m and my answer was 3888 which is wrong

also I know that the marginal revenue is the derivative of the revenue function but i still cant seem to find the right answer