- #1
Physser
- 2
- 0
Homework Statement
Asked to calculate the relativistic correction, to the differential scattering cross section which is given by the equation below in terms of E, E0 and θ where E0= .511 MeV.
with 100MeV electrons from an Au nuclei at certain angles θ.
Homework Equations
Relativistic correction = [ 1 - (v0)2/c2.sin2(θ/2)]
The Attempt at a Solution
I figure the electron energy is kinetic so 100MeV = 1/2 m v2
and by re-arranging for v i get; v = 200/E0
then plugging into the formula for v gives, (at 20°=θ)
[1 - 200/E0c2.0.03 ]
I'm not sure, first of all if this is correct do far and second of all how to express in terms of E, could it be to use;
E = √(1-(v/c)2).mc2 and somehow re-arrange?
Any help would be greatly appreciated.
Cheers.