- #1
schattenjaeger
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d(chi)/dt =l/(mr^2), I don't see how to get there
if you use the definition of angular momentum, you get l=r x mv(vectors where appropriate)
so you can write v as v=dr/dt*r + rdx/dt*x where x is the symbol chi(close enough)and that r and x at the end of the two expressions are unit vectors
So you can write the magnitude of l=|mr*v| where v is as above. Then I'm stumped
d(chi)/dt =l/(mr^2), I don't see how to get there
if you use the definition of angular momentum, you get l=r x mv(vectors where appropriate)
so you can write v as v=dr/dt*r + rdx/dt*x where x is the symbol chi(close enough)and that r and x at the end of the two expressions are unit vectors
So you can write the magnitude of l=|mr*v| where v is as above. Then I'm stumped