- Thread starter
- #1

#### Dhamnekar Winod

##### Active member

- Nov 17, 2018

- 100

Answer given is 143. But my logic is for any sum, at least 2 numbers are needed. So, there are $\binom{15} {2} + \binom{15}{3}+...\binom{15}{15} $ distinct sums.

So, I think answer 143 is wrong.

What is your opinion?