- #1
mateomy
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Im looking over an example that was given in class that I jotted down in my notes; the question posed was...A 320 kg motorcycle includes two wheels each of which is 52 cm in diameter and has rotational inertia 2.1 kg*m^2. The cycle and its 75 kg rider are coasting at 85km/hr on a flat road when they encounter a hill. If the cycle rolls up the hill with no applied power and no significant internal friction, what vertical height will it reach?
So anyway...professor used the Conservation of Energy...
[tex]
Mgh= \frac{1}{2}Mv^2 + \frac{1}{2}I\omega^2 + \frac{1}{2}I\omega^2
[/tex]
Im just confused on the last two terms. Is there 2 of them because of the two wheels?
So anyway...professor used the Conservation of Energy...
[tex]
Mgh= \frac{1}{2}Mv^2 + \frac{1}{2}I\omega^2 + \frac{1}{2}I\omega^2
[/tex]
Im just confused on the last two terms. Is there 2 of them because of the two wheels?