Understanding Einstein's Relativity: From Energy Equations to Series Development

  • Thread starter OneEye
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In summary, Dr. Einstein explains in his book, Relativity, that the energy of a material point with mass m is no longer given by the familiar equation m(v/c^2), but rather by the expression (mc^2)/√(1-(v^2/c^2)). He then discusses how this expression can be further developed into a series, known as a Taylor's series, to calculate the kinetic energy. This involves taking derivatives of the function (1+ x^2/c^2)^(-1/2) and plugging in the value of x as v, then multiplying by mc^2. This is known as the "McLaurin series". This method allows for a more precise calculation of kinetic
  • #1
OneEye
In Relativity, (p. 45), Dr. Einstein says:

...the energy of a material point of mass m is no longer gievn by the well-known expression

[tex]m { v \over c^2 } [/tex]

but by the expression

[tex] { m c^2 } \over \sqrt { 1 - { v^2 \over c^2 } } [/tex]

...If we develop the expression for the kinetic energy in the form of a series, we obtain

[tex]mc^2 + m { v^2 \over 2 } + { 3 \over 8 } m { v^4 \over c^2 } . . . .[/tex]

How does one get from the second equation to the third? What is meant by "develop[ing] the expression... in the form of a series"?

Any help would be more than appreciated.
 
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  • #2
One way is to use a "Taylor's series" expansion.

If f is any function, analytic at x0 then
f(x)= f(x0)+ f '(x0)(x- x0)+ (f''(x0)/2)(x- x0)2+ (f'''(x0)/6)(x- x0)3+ ...
the general term is (f(n)(x0)/n!)(x-x0)n where f(n) is the nth derivative.

In particular, use the "McLaurin series" which is the Taylor's series with x0= 0 and f(x)= (1+ x2/c2)-1/2, set x= v, and then multiply by mc2.
 
  • #3
HoI - Thanks - I suspected something like this, but lacked the mathematical toolkit to know what exactly was meant.

Most helpful!
 

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