- Thread starter
- #1

- Thread starter Vi Nguyen
- Start date

- Thread starter
- #1

- Mar 1, 2012

- 644

logarithm to exponential relationship ...Rewrite in exponential form:

Log(6) 1294 = 4

sure that isn't 1296 ?

Log(w) v = t

if you meantwto be the base of the logarithm ... $w^t = v$

Ln(1/4) = x

$e^x = \dfrac{1}{4}$

Evaluate

Log(4) 64 = ?

note that $4^3 = 64$

Log(16) 4 = ?

note $16^{1/2} = 4$

$\log_b(a) = c \implies b^c = a$

- Thread starter
- #3