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Homework Statement
Initially, sphere A has a charge of –10e and sphere B has a charge of +20e. The spheres are made of conducting material and are identical in size. If the spheres then touch, what is the resulting charge on sphere A? a) +10e, b) -10e, c) -5e, d) +5e
The attempt at a solution
Sphere B -> [itex]20e-\left(\frac{+20e-10e}{2}\right) = 20e - 5e = 15e[/itex]. So there is a loss of 5e in Sphere B. This would mean that the only -5e remains on Sphere B?
The Problem
However, the answer is +5e. Why is this? There is a loss of 5e in Sphere B. This would mean that the only -5e remains on Sphere B?
Initially, sphere A has a charge of –10e and sphere B has a charge of +20e. The spheres are made of conducting material and are identical in size. If the spheres then touch, what is the resulting charge on sphere A? a) +10e, b) -10e, c) -5e, d) +5e
The attempt at a solution
Sphere B -> [itex]20e-\left(\frac{+20e-10e}{2}\right) = 20e - 5e = 15e[/itex]. So there is a loss of 5e in Sphere B. This would mean that the only -5e remains on Sphere B?
The Problem
However, the answer is +5e. Why is this? There is a loss of 5e in Sphere B. This would mean that the only -5e remains on Sphere B?